Consider the function *f*(*μ*)=∑*n**i*=1(*x**i*−*μ*)2, where *x**i*=*i*,*i*=1,2,…,*n*

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What is the first and second derivative of *f*(*μ*)?

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f′(μ)=−2∑ni=1(xi−μ) and f′′(μ)=2n