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Home/ Questions/Q 8822
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Alek Richter
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Alek RichterEnlightened
Asked: January 11, 20222022-01-11T09:41:09+00:00 2022-01-11T09:41:09+00:00

How to dynamically allocate arrays in C++

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I know how to dynamically allocate space for an array in C. It can be done as follows:

L = (int*)malloc(mid*sizeof(int)); 

and the memory can be released by:

free(L);

How do I achieve the equivalent in C++?

Specifically, how do I use the new and delete[] keywords? Especially in the context of creating/destroying a linked list node, or creating and destroying an array whose size is given by a variable during compile time?

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  1. Alek Richter Enlightened
    2022-01-11T09:41:28+00:00Added an answer on January 11, 2022 at 9:41 am

    int* L = new int[mid];
    delete[] L;

    for arrays (which is what you want) or

    int* L = new int;
    delete L;

    for single elements.

    But it’s more simple to use vector, or use smartpointers, then you don’t have to worry about memory management.

    std::vector L(mid);

    L.data() gives you access to the int[] array buffer and you can L.resize() the vector later.

    auto L = std::make_unique(mid);

    L.get() gives you a pointer to the int[] array.

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