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Home/ Questions/Q 8977
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Alek Richter
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Alek RichterEnlightened
Asked: January 11, 20222022-01-11T10:44:57+00:00 2022-01-11T10:44:57+00:00

How to prevent errno 32 broken pipe?

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Currently I am using an app built in python. When I run it in personal computer, it works without problems.

However, when I move it into a production server. It keeps showing me the error attached as below:.

I’ve done some research and I got the reason that the end user browser stops the connection while the server is still busy sending data.

I wonder why did it happen and what is the root cause that prevents it from running properly in production server, while it works on my personal computer. Any advice is appreciated

    Exception happened during processing of request from ('127.0.0.1', 34226)
Traceback (most recent call last):
  File "/usr/lib/python2.7/SocketServer.py", line 284, in
_handle_request_noblock
    self.process_request(request, client_address)
  File "/usr/lib/python2.7/SocketServer.py", line 310, in process_request
    self.finish_request(request, client_address)
  File "/usr/lib/python2.7/SocketServer.py", line 323, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "/usr/lib/python2.7/SocketServer.py", line 641, in __init__
    self.finish()
  File "/usr/lib/python2.7/SocketServer.py", line 694, in finish
    self.wfile.flush()
  File "/usr/lib/python2.7/socket.py", line 303, in flush
    self._sock.sendall(view[write_offset:write_offset+buffer_size])
error: [Errno 32] Broken pipe
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  1. Alek Richter Enlightened
    2022-01-11T10:45:13+00:00Added an answer on January 11, 2022 at 10:45 am

    Your server process has received a SIGPIPE writing to a socket. This usually happens when you write to a socket fully closed on the other (client) side. This might be happening when a client program doesn’t wait till all the data from the server is received and simply closes a socket (using close function).

    In a C program you would normally try setting to ignore SIGPIPE signal or setting a dummy signal handler for it. In this case a simple error will be returned when writing to a closed socket. In your case a python seems to throw an exception that can be handled as a premature disconnect of the client.

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