The other question that you posted was multiple choice. If this one is too, then there are probably some answers that can be eliminated.

Without meaning to discount others’ comments about “there is no one right answer,” given the scope of middle school math there are some reasonable things that can be said about the sequence 2,7,26,101,400,…

The next number should reasonably be bigger than 400

. We don’t see any example given that suggests the contrary. (If 300
were a choice, it could be eliminated.)
The next number should be quite a bit bigger, given that the difference between consecutive elements in the sequence have a wider gap each time. (If 401
were a choice, it could be reasonably eliminated.)
The next number should be close to four times bigger, looking at what’s presented. 101
to 400

is the strongest suggestion of this but it’s reasonable for the other pairs of consecutive numbers as well.

Now, if the last point is noticed, then we can home in. Starting with 2
, multiplying by 4

each time would give

2,8,32,128,512

Not quite right, so let’s look at the first two numbers. Let’s multiply by 4
and subtract 1

each time:

2,7,27,107,427

The second to third jump is only off by one, so maybe … (maybe!) … we increase the number we subtract each time by one:

2,7,26,101,400

There it is.

If we apply the pattern again, then we get 4×400−5=1595.

I just looked at the sequence and played with it.