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Home/ Questions/Q 9033
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Alek Richter
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Alek RichterEnlightened
Asked: January 13, 20222022-01-13T10:03:49+00:00 2022-01-13T10:03:49+00:00

Short circuit Array.forEach like calling break

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[1,2,3].forEach(function(el) {
    if(el === 1) break;
});

How can I do this using the new forEach method in JavaScript? I’ve tried return;, return false; and break. break crashes and return does nothing but continue iteration.

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  1. Alek Richter Enlightened
    2022-01-13T10:04:13+00:00Added an answer on January 13, 2022 at 10:04 am

    There’s no built-in ability to break in forEach. To interrupt execution you would have to throw an exception of some sort. eg.

    var BreakException = {};

    try {
    [1, 2, 3].forEach(function(el) {
    console.log(el);
    if (el === 2) throw BreakException;
    });
    } catch (e) {
    if (e !== BreakException) throw e;
    }

    Expand snippet

    JavaScript exceptions aren’t terribly pretty. A traditional for loop might be more appropriate if you really need to break inside it.
    Use Array#some

    Instead, use Array#some:

    [1, 2, 3].some(function(el) {
    console.log(el);
    return el === 2;
    });

    Expand snippet

    This works because some returns true as soon as any of the callbacks, executed in array order, return true, short-circuiting the execution of the rest.

    some, its inverse every (which will stop on a return false), and forEach are all ECMAScript Fifth Edition methods which will need to be added to the Array.prototype on browsers where they’re missing.

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